What is the integral from 1 to 3 of 6/x ?

The integral from 1 to 3 of 6/x is 6ln(3)

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integral from 1 to 3 of 6/x

\int_{1}^{3} \frac{6}{x} d x

6 ln (3)

Decimal Notation

6.59167 \dots

Solution steps

\int_{1}^{3} \frac{6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{3} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 6 [ln ∣ x ∣]_{1}^{3}

Compute the boundaries:

ln (3)

= 6 ln (3)

f (x) = 4 x sin (x) cos (x)

(- 3, - 10), (4, 5)

y = 5 x^{4} f (x)

20 y^{^{''}} - y^{^{'}} + 7 y = 0

\frac{d}{d x} (\frac{n}{x})

What is the integral from 1 to 3 of 6/x ?
The integral from 1 to 3 of 6/x is 6ln(3)