What is the integral from 2 to 5 of x^3 ?

The integral from 2 to 5 of x^3 is 609/4

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integral from 2 to 5 of x^3

\int_{2}^{5} x^{3} d x

\frac{609}{4}

Decimal Notation

152.25

Solution steps

\int_{2}^{5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{2}^{5}

= [\frac{x ^{4}}{4}]_{2}^{5}

Compute the boundaries:

\frac{609}{4}

= \frac{609}{4}

\int (u^{5} - 3 u^{4} - u^{2} + \frac{2}{7}) d u

- \frac{3}{x}

\frac{d}{d x} (2 x sin (x) + cos (x) x^{2})

x \to \infty lim (3 \cdot x)

\int \frac{17}{x ln ( 3 x )} d x

What is the integral from 2 to 5 of x^3 ?
The integral from 2 to 5 of x^3 is 609/4