What is the limit as x approaches 3 of (2x^2-4x-8)^6 ?

The limit as x approaches 3 of (2x^2-4x-8)^6 is 64

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limit as x approaches 3 of (2x^2-4x-8)^6

x \to 3 lim ((2 x^{2} - 4 x - 8)^{6})

64

Solution steps

x \to 3 lim ((2 x^{2} - 4 x - 8)^{6})

Plug in the value

x = 3

= (2 \cdot 3^{2} - 4 \cdot 3 - 8)^{6}

Simplify

(2 \cdot 3^{2} - 4 \cdot 3 - 8)^{6} : 64

= 64

\frac{\partial}{\partial x} (\frac{4 x}{y})

\int \frac{4 x - 2}{x ^{3} - x ^{2} - 2 x} d x

y = sin (t^{3})

\int_{0}^{N} e^{- s t} e^{3 t} d t

\int \frac{2}{3} x^{2} d x

What is the limit as x approaches 3 of (2x^2-4x-8)^6 ?
The limit as x approaches 3 of (2x^2-4x-8)^6 is 64