What is the derivative of f(x)=(5x)/(x-3) ?

The derivative of f(x)=(5x)/(x-3) is -(15)/((x-3)^2)

What is the first derivative of f(x)=(5x)/(x-3) ?

The first derivative of f(x)=(5x)/(x-3) is -(15)/((x-3)^2)

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derivative of

f (x) = \frac{5 x}{x - 3}

- \frac{15}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5 x}{x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{x}{x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 5 \cdot \frac{\frac{d x}{d x} ( x - 3 ) - \frac{d}{d x} ( x - 3 ) x}{( x - 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x - 3) = 1

= 5 \cdot \frac{1 \cdot ( x - 3 ) - 1 \cdot x}{( x - 3 ) ^{2}}

Simplify

5 \cdot \frac{1 \cdot ( x - 3 ) - 1 \cdot x}{( x - 3 ) ^{2}} : - \frac{15}{( x - 3 ) ^{2}}

= - \frac{15}{( x - 3 ) ^{2}}

n = 1 \sum \infty (2)^{n - 1}

\frac{1}{x ^{2} + 1} (\frac{d y}{d x}) = x e^{y}

\int \frac{4}{x ^{2} - 1} d x

\frac{d}{d x} (- \frac{1}{2} sin (x))

\int \frac{x ^{2}}{a ^{2} - x ^{2}} d x

What is the derivative of f(x)=(5x)/(x-3) ?
The derivative of f(x)=(5x)/(x-3) is -(15)/((x-3)^2)
What is the first derivative of f(x)=(5x)/(x-3) ?
The first derivative of f(x)=(5x)/(x-3) is -(15)/((x-3)^2)