What is the derivative of 8x^6+5w^2+7w ?

The derivative of 8x^6+5w^2+7w is 48x^5

What is the first derivative of 8x^6+5w^2+7w ?

The first derivative of 8x^6+5w^2+7w is 48x^5

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derivative of

8 x^{6} + 5 w^{2} + 7 w

48 x^{5}

Solution steps

\frac{d}{d x} (8 x^{6} + 5 w^{2} + 7 w)

Treat

w

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{6}) + \frac{d}{d x} (5 w^{2}) + \frac{d}{d x} (7 w)

\frac{d}{d x} (8 x^{6}) = 48 x^{5}

\frac{d}{d x} (5 w^{2}) = 0

\frac{d}{d x} (7 w) = 0

= 48 x^{5} + 0 + 0

Simplify

= 48 x^{5}

y = 3 x^{2} + 10 x + 2, at x = 1

x \to \infty lim (2^{2 x})

y = \frac{3 x - 1}{6 x + 5}

(\frac{1}{2} arcsin (x) + \frac{1}{4} sin (2 arcsin (x)))^{^{'}}

x \cdot g (x) \cdot f (x)

What is the derivative of 8x^6+5w^2+7w ?
The derivative of 8x^6+5w^2+7w is 48x^5
What is the first derivative of 8x^6+5w^2+7w ?
The first derivative of 8x^6+5w^2+7w is 48x^5