What is the derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) ?

The derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) is (28)/(9x^{2/3)}

What is the first derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) ?

The first derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) is (28)/(9x^{2/3)}

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derivative of

\frac{28}{9 x ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{x ^{\frac{1}{3}}}{3}) = \frac{1}{9 x ^{\frac{2}{3}}}

= 7 (\frac{1}{3 x ^{\frac{2}{3}}} + \frac{1}{9 x ^{\frac{2}{3}}})

Simplify

7 (\frac{1}{3 x ^{\frac{2}{3}}} + \frac{1}{9 x ^{\frac{2}{3}}}) : \frac{28}{9 x ^{\frac{2}{3}}}

= \frac{28}{9 x ^{\frac{2}{3}}}

f (x) = \frac{1}{1 + x ^{2}}, (- 1, \frac{1}{2})

f (x) = \frac{sin ( x )}{2 x}

\int_{- π}^{π} sin (x) sin (n x) d x

\frac{1}{3 + 5 x}

y = x^{\frac{5}{2}} e^{x}

What is the derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) ?
The derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) is (28)/(9x^{2/3)}
What is the first derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) ?
The first derivative of 7(\sqrt[3]{x}+(x^{1/3})/3) is (28)/(9x^{2/3)}