What is the tangent of f(x)=-3-6x^2,(-2,27) ?

The tangent of f(x)=-3-6x^2,(-2,27) is y=60x+147 \lor y=-12x+3

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tangent of f(x)=-3-6x^2,(-2,27)

tangent of

f (x) = - 3 - 6 x^{2}, (- 2, 27)

y = 60 x + 147 or y = - 12 x + 3

Solution steps

Slope of the tangent line at

(- 2, 27) : m = \frac{- 6 x ^{2} - 30}{x + 2}

Find the slope of

f (x) = - 3 - 6 x^{2} : m = - 12 x

Solve

- 12 x = \frac{- 6 x ^{2} - 30}{x + 2} : x = - 5, x = 1

Find the tangent line at

x = - 5 : y = 60 x + 147

Find the tangent line at

x = 1 : y = - 12 x + 3

y = 60 x + 147 or y = - 12 x + 3

f (t) = t sin (t)

\frac{d}{d x} (tan (\frac{x ^{2}}{2 x + 3}))

\int - csc (x) d x

\frac{\partial}{\partial x} (ln (y) + 2 x y^{3})

y^{^{''}} + 9 y = 3 x e^{2 x}

What is the tangent of f(x)=-3-6x^2,(-2,27) ?
The tangent of f(x)=-3-6x^2,(-2,27) is y=60x+147 \lor y=-12x+3