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Popular >

integral of 1/(6+x)

Solution

\int \frac{1}{6 + x} d x

Solution

ln ∣ 6 + x ∣ + C

Solution steps

\int \frac{1}{6 + x} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 6 + x

= ln ∣ 6 + x ∣

Add a constant to the solution

= ln ∣ 6 + x ∣ + C

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Frequently Asked Questions (FAQ)

What is the integral of 1/(6+x) ?
The integral of 1/(6+x) is ln|6+x|+C