What is the derivative of 3x^4-4x^3 ?

The derivative of 3x^4-4x^3 is 12x^3-12x^2

What is the first derivative of 3x^4-4x^3 ?

The first derivative of 3x^4-4x^3 is 12x^3-12x^2

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\frac{d}{d x} (3 x^{4} - 4 x^{3})

12 x^{3} - 12 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (4 x^{3})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

= 12 x^{3} - 12 x^{2}

f (x) = \frac{3 x}{4} - 2

(2 - t) (4 + t^{2})^{- 1}

\frac{d}{d x} (- \frac{x ^{4}}{4} + x^{3} - x^{2})

\int x^{3} y^{4} d x

\frac{d}{d x} (e^{3 x} (- 2 sin (2 x) + 3 cos (2 x)))

What is the derivative of 3x^4-4x^3 ?
The derivative of 3x^4-4x^3 is 12x^3-12x^2
What is the first derivative of 3x^4-4x^3 ?
The first derivative of 3x^4-4x^3 is 12x^3-12x^2