What is the derivative of-64sin(2x) ?

The derivative of-64sin(2x) is -128cos(2x)

What is the first derivative of-64sin(2x) ?

The first derivative of-64sin(2x) is -128cos(2x)

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\frac{d}{d x} (- 64 sin (2 x))

- 128 cos (2 x)

Solution steps

\frac{d}{d x} (- 64 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 64 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 64 cos (2 x) \cdot 2

Simplify

= - 128 cos (2 x)

y = 6 e^{x}, at x = 1

\int \frac{- 8 e ^{2 x}}{e ^{2 x} + 3 e ^{x} + 2} d x

\int cos^{2} (θ) sin^{4} (θ) d θ

x \frac{d y}{d x} = x^{3} + 16 x^{3} y

d x + e^{6 x} d y = 0

What is the derivative of-64sin(2x) ?
The derivative of-64sin(2x) is -128cos(2x)
What is the first derivative of-64sin(2x) ?
The first derivative of-64sin(2x) is -128cos(2x)