What is the sum from n=0 to infinity of 2^{2n} ?

The sum from n=0 to infinity of 2^{2n} is diverges

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sum from n=0 to infinity of 2^{2n}

n = 0 \sum \infty 2^{2 n}

diverges

Solution steps

n = 0 \sum \infty 2^{2 n}

Simplify

2^{2 n} : 4^{n}

= n = 0 \sum \infty 4^{n}

Apply Series Geometric Test:

diverges

= diverges

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What is the sum from n=0 to infinity of 2^{2n} ?
The sum from n=0 to infinity of 2^{2n} is diverges