What is the derivative of 2x^2+3x-1 ?

The derivative of 2x^2+3x-1 is 4x+3

What is the first derivative of 2x^2+3x-1 ?

The first derivative of 2x^2+3x-1 is 4x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x^{2} + 3 x - 1)

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 4 x + 3 - 0

Simplify

= 4 x + 3

\int 7 x^{- 3} d x

f (x) = x^{1}

n = 0 \sum \infty \frac{n}{( 2 ^{(n - 1)} )}

\frac{d}{d x} (\frac{1}{16 - x ^{2} - 5 x})

\int_{2}^{5} (\frac{3 x + 3}{x ^{2}}) d x

What is the derivative of 2x^2+3x-1 ?
The derivative of 2x^2+3x-1 is 4x+3
What is the first derivative of 2x^2+3x-1 ?
The first derivative of 2x^2+3x-1 is 4x+3