What is the derivative of 4x^3-4x ?

The derivative of 4x^3-4x is 12x^2-4

What is the first derivative of 4x^3-4x ?

The first derivative of 4x^3-4x is 12x^2-4

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\frac{d}{d x} (4 x^{3} - 4 x)

12 x^{2} - 4

Solution steps

\frac{d}{d x} (4 x^{3} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (4 x) = 4

= 12 x^{2} - 4

f (x) = 500 - 500 t^{- 1}

x \to - 5 lim (x)

\frac{4 x}{x ^{2} + 1}

\int_{0}^{8} 1 + x d x

x^{3} - 5 x, 4 x, - 3, 3

What is the derivative of 4x^3-4x ?
The derivative of 4x^3-4x is 12x^2-4
What is the first derivative of 4x^3-4x ?
The first derivative of 4x^3-4x is 12x^2-4