What is the tangent of-3cos(x),\at x=-pi/4 ?

The tangent of-3cos(x),\at x=-pi/4 is y=-3/(sqrt(2))x-3/(sqrt(2))-(3pi)/(4sqrt(2))

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tangent of-3cos(x),\at x=-pi/4

tangent of

- 3 cos (x), at x = - \frac{π}{4}

y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, - \frac{3}{2})

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

Compute the slope of

y = - 3 cos (x)

x = - \frac{π}{4} : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- \frac{π}{4}, - \frac{3}{2}) : y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

x \to \infty lim (11 + \frac{4}{x ^{2}})

\frac{d}{d x} (\frac{4}{3} π x^{2})

f (x) = 12 x, (1, 12)

\int sec^{11} (x) d x

x^{\frac{6}{5}} + e^{- 3 x}

What is the tangent of-3cos(x),\at x=-pi/4 ?
The tangent of-3cos(x),\at x=-pi/4 is y=-3/(sqrt(2))x-3/(sqrt(2))-(3pi)/(4sqrt(2))