What is the tangent of 2 1/x ,\at x=3 ?

The tangent of 2 1/x ,\at x=3 is y=-2/9 x+4/3

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tangent of 2 1/x ,\at x=3

tangent of

2 \frac{1}{x}, at x = 3

y = - \frac{2}{9} x + \frac{4}{3}

Solution steps

Find the tangent point:

(3, \frac{2}{3})

Find the slope of

y = 2 \frac{1}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = 2 \frac{1}{x}

x = 3 : m = - \frac{2}{9}

Find the line with slope m=

- \frac{2}{9}

and passing through

(3, \frac{2}{3}) : y = - \frac{2}{9} x + \frac{4}{3}

y = - \frac{2}{9} x + \frac{4}{3}

\int \frac{9 x ^{2} - 1}{x} d x

\int (1 - 2 e^{t a n (x)}) sec^{2} (x) d x

x \to 4 - lim (\frac{x + 2}{x - 4})

x \to 0 lim (\frac{lo g _{e} ( 1 + 3 x ^{2} )}{x ( e ^{x} - 1 )})

\frac{d}{d x} (sin^{2} (3 x - 2))

What is the tangent of 2 1/x ,\at x=3 ?
The tangent of 2 1/x ,\at x=3 is y=-2/9 x+4/3