What is the solution for (x^4+y^2)dx-xydy=0 ?

The solution for (x^4+y^2)dx-xydy=0 is y=xsqrt(x^2+c_{1)},y=-xsqrt(x^2+c_{1)}

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(x^4+y^2)dx-xydy=0

(x^{4} + y^{2}) d x - x y d y = 0

y = x x^{2} + c_{1}, y = - x x^{2} + c_{1}

Solution steps

(x^{4} + y^{2}) d x - x y d y = 0

Solve Bernoulli ODE:

y = x x^{2} + c_{1}, y = - x x^{2} + c_{1}

y = x x^{2} + c_{1}, y = - x x^{2} + c_{1}

\int (tan (θ)) d θ

x \to 0 lim (\frac{sin ( π x )}{x})

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\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{5}{x ^{4}}) (x + 3 x^{3}))

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What is the solution for (x^4+y^2)dx-xydy=0 ?
The solution for (x^4+y^2)dx-xydy=0 is y=xsqrt(x^2+c_{1)},y=-xsqrt(x^2+c_{1)}