What is the solution for f^{''}(x)= 4/(x^2) ?

The solution for f^{''}(x)= 4/(x^2) is f(x)=-4ln(x)+c_{1}x+c_{2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f^{''}(x)= 4/(x^2)

f^{^{''}} (x) = \frac{4}{x ^{2}}

f (x) = - 4 ln (x) + c_{1} x + c_{2}

Solution steps

f^{''} (x) = \frac{4}{x ^{2}}

Solve

f^{''} (x) = \frac{4}{x ^{2}} : f^{'} (x) = - \frac{4}{x} + c_{1}

Solve

f^{'} (x) = - \frac{4}{x} + c_{1} : f (x) = - 4 ln (x) + c_{1} x + c_{2}

f (x) = - 4 ln (x) + c_{1} x + c_{2}

\int \frac{1}{x ^{2} 49 x ^{2} + 16} d x

\frac{d}{d t} (e^{t a n (π t)})

\frac{x ^{2}}{e ^{x}}

\int arcsin (x) 1 - x d x

r \to 3 lim (\frac{4}{3} π r^{3})

What is the solution for f^{''}(x)= 4/(x^2) ?
The solution for f^{''}(x)= 4/(x^2) is f(x)=-4ln(x)+c_{1}x+c_{2}