What is (\partial)/(\partial z)(zy^2(t+1)) ?

The answer to (\partial)/(\partial z)(zy^2(t+1)) is y^2(t+1)

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(\partial)/(\partial z)(zy^2(t+1))

\frac{\partial}{\partial z} (z y^{2} (t + 1))

y^{2} (t + 1)

Solution steps

\frac{\partial}{\partial z} (z y^{2} (t + 1))

Treat

y, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} (t + 1) \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= y^{2} (t + 1) \cdot 1

Simplify

= y^{2} (t + 1)

\int \frac{sec ( y )}{sin ( y )} d y

\frac{\partial}{\partial x} (\frac{1}{x ^{2}})

\frac{2}{( - 2 s + 10 )}

\frac{d}{d x} (f (x) (x))

\frac{d}{d x} (3 x^{2} - 2 x + 7)

What is (\partial)/(\partial z)(zy^2(t+1)) ?
The answer to (\partial)/(\partial z)(zy^2(t+1)) is y^2(t+1)