What is the derivative of 2csc(x+4cot(x)) ?

The derivative of 2csc(x+4cot(x)) is -2cot(x)csc(x)-4csc^2(x)

What is the first derivative of 2csc(x+4cot(x)) ?

The first derivative of 2csc(x+4cot(x)) is -2cot(x)csc(x)-4csc^2(x)

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\frac{d}{d x} (2 csc (x) + 4 cot (x))

- 2 cot (x) csc (x) - 4 csc^{2} (x)

Solution steps

\frac{d}{d x} (2 csc (x) + 4 cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 csc (x)) + \frac{d}{d x} (4 cot (x))

\frac{d}{d x} (2 csc (x)) = - 2 cot (x) csc (x)

\frac{d}{d x} (4 cot (x)) = - 4 csc^{2} (x)

= - 2 cot (x) csc (x) - 4 csc^{2} (x)

(- 3, 4), (2, - 9)

\int tan^{- \frac{3}{2}} (x) sec^{4} (x) d x

\frac{d y}{d x} = (1 + y^{2}) tan (x)

\frac{d}{d x} (- 6 e^{- 6 x})

What is the derivative of 2csc(x+4cot(x)) ?
The derivative of 2csc(x+4cot(x)) is -2cot(x)csc(x)-4csc^2(x)
What is the first derivative of 2csc(x+4cot(x)) ?
The first derivative of 2csc(x+4cot(x)) is -2cot(x)csc(x)-4csc^2(x)