What is the derivative of 1-2sin(x) ?

The derivative of 1-2sin(x) is -2cos(x)

What is the first derivative of 1-2sin(x) ?

The first derivative of 1-2sin(x) is -2cos(x)

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\frac{d}{d x} (1 - 2 sin (x))

- 2 cos (x)

Solution steps

\frac{d}{d x} (1 - 2 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (2 sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

= 0 - 2 cos (x)

Simplify

= - 2 cos (x)

f (x) = 6 e^{x}

h \to + 6 lim (\frac{4 h}{h - 6})

f (x) = 9 - x

\int_{0}^{1} 3 e^{x^{2}} d x

f (x) = x^{3} + 2 x^{2} + 4 x, at x = - 1

What is the derivative of 1-2sin(x) ?
The derivative of 1-2sin(x) is -2cos(x)
What is the first derivative of 1-2sin(x) ?
The first derivative of 1-2sin(x) is -2cos(x)