What is laplacetransform 3e^{2t}sin(4t) ?

The answer to laplacetransform 3e^{2t}sin(4t) is (12)/((s-2)^2+16)

Popular >

laplacetransform 3e^{2t}sin(4t)

laplace transform

3 e^{2 t} sin (4 t)

\frac{12}{( s - 2 ) ^{2} + 16}

Solution steps

L {3 e^{2 t} sin (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {e^{2 t} sin (4 t)}

L {e^{2 t} sin (4 t)} : \frac{4}{( s - 2 ) ^{2} + 16}

= 3 \cdot \frac{4}{( s - 2 ) ^{2} + 16}

Refine

3 \frac{4}{( s - 2 ) ^{2} + 16} : \frac{12}{( s - 2 ) ^{2} + 16}

= \frac{12}{( s - 2 ) ^{2} + 16}

\frac{\partial}{\partial β} (sin (α) cos (β))

\frac{\partial}{\partial y} (x^{y^{z}})

\frac{d}{d x} (ln (\frac{2 x + 1}{x ^{2} - 2}))

\frac{\partial}{\partial x} (4 x^{0.5} + 2 x^{0.25})

\int 2 x e^{4 x} d x

What is laplacetransform 3e^{2t}sin(4t) ?
The answer to laplacetransform 3e^{2t}sin(4t) is (12)/((s-2)^2+16)