What is (\partial)/(\partial x)(x-y+xy) ?

The answer to (\partial)/(\partial x)(x-y+xy) is y+1

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(\partial)/(\partial x)(x-y+xy)

\frac{\partial}{\partial x} (x - y + x y)

y + 1

Solution steps

\frac{\partial}{\partial x} (x - y + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x y) = y

= 1 - 0 + y

Simplify

= y + 1

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What is (\partial)/(\partial x)(x-y+xy) ?
The answer to (\partial)/(\partial x)(x-y+xy) is y+1