What is the integral of 1/(x^{-1/2)} ?

The integral of 1/(x^{-1/2)} is 2/3 x^{3/2}+C

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integral of 1/(x^{-1/2)}

\int \frac{1}{x ^{- \frac{1}{2}}} d x

\frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int \frac{1}{x ^{- \frac{1}{2}}} d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + C

\frac{d}{d x} (x (4 x - 12)^{3})

\int - \frac{4000}{x ^{2}} d x

\frac{d}{d x} (sin^{2} (x) cos^{3} (x))

x \to 0 lim (x sin (\frac{4}{x}))

y^{^{'}} + y + 2 cos (x) = 0

What is the integral of 1/(x^{-1/2)} ?
The integral of 1/(x^{-1/2)} is 2/3 x^{3/2}+C