What is the derivative of 3x^2+2x ?

The derivative of 3x^2+2x is 6x+2

What is the first derivative of 3x^2+2x ?

The first derivative of 3x^2+2x is 6x+2

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\frac{d}{d x} (3 x^{2} + 2 x)

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 6 x + 2

\frac{\partial}{\partial x} (sin (x^{3} + y^{2}))

y^{^{'}} + 5 y = 1

(- 3, 2), (5, - 4)

x \to - 1 lim (x^{2} + x + 1)

\frac{d}{d x} (\frac{x ^{2}}{( 1 + x )})

What is the derivative of 3x^2+2x ?
The derivative of 3x^2+2x is 6x+2
What is the first derivative of 3x^2+2x ?
The first derivative of 3x^2+2x is 6x+2