What is laplacetransform 6e^{-2t} ?

The answer to laplacetransform 6e^{-2t} is 6/(s+2)

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laplacetransform 6e^{-2t}

laplace transform

6 e^{- 2 t}

\frac{6}{s + 2}

Solution steps

L {6 e^{- 2 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 6 L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= 6 \cdot \frac{1}{s + 2}

Refine

6 \frac{1}{s + 2} : \frac{6}{s + 2}

= \frac{6}{s + 2}

\frac{d}{d y} (ln (cos (\frac{x}{y ^{2}})))

\int ln (x^{n}) d x

\int \frac{sec ^{4} ( x )}{tan ^{5} ( x )} d x

(\frac{3}{10}, - \frac{1}{2}), (\frac{1}{5}, \frac{1}{5})

\frac{\partial}{\partial x} (y^{3} sin (5 x))

What is laplacetransform 6e^{-2t} ?
The answer to laplacetransform 6e^{-2t} is 6/(s+2)