What is the derivative of (2^{2/3}-x^{2/3}^{3/2}) ?

The derivative of (2^{2/3}-x^{2/3}^{3/2}) is -((2^{2/3}-x^{2/3})^{1/2})/(x^{1/3)}

What is the first derivative of (2^{2/3}-x^{2/3}^{3/2}) ?

The first derivative of (2^{2/3}-x^{2/3}^{3/2}) is -((2^{2/3}-x^{2/3})^{1/2})/(x^{1/3)}

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\frac{d}{d x} ((2^{\frac{2}{3}} - x^{\frac{2}{3}})^{\frac{3}{2}})

- \frac{( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} ((2^{\frac{2}{3}} - x^{\frac{2}{3}})^{\frac{3}{2}})

Apply the chain rule:

\frac{3 ( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{2} \frac{d}{d x} (2^{\frac{2}{3}} - x^{\frac{2}{3}})

= \frac{3 ( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{2} \frac{d}{d x} (2^{\frac{2}{3}} - x^{\frac{2}{3}})

\frac{d}{d x} (2^{\frac{2}{3}} - x^{\frac{2}{3}}) = - \frac{2}{3 x ^{\frac{1}{3}}}

= \frac{3 ( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{2} (- \frac{2}{3 x ^{\frac{1}{3}}})

Simplify

\frac{3 ( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{2} (- \frac{2}{3 x ^{\frac{1}{3}}}) : - \frac{( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{x ^{\frac{1}{3}}}

= - \frac{( 2 ^{\frac{2}{3}} - x ^{\frac{2}{3}} ) ^{\frac{1}{2}}}{x ^{\frac{1}{3}}}

\frac{d}{d x} (\frac{x ^{e^{x}}}{1 + x ^{2}})

\frac{d}{d x} (sin (e^{x}))

\frac{d}{d θ} (e^{2 θ})

\int \frac{1}{x ( ln ( x ^{2} ) )} d x

\int ln (e^{x y} cos (x)) d y

What is the derivative of (2^{2/3}-x^{2/3}^{3/2}) ?
The derivative of (2^{2/3}-x^{2/3}^{3/2}) is -((2^{2/3}-x^{2/3})^{1/2})/(x^{1/3)}
What is the first derivative of (2^{2/3}-x^{2/3}^{3/2}) ?
The first derivative of (2^{2/3}-x^{2/3}^{3/2}) is -((2^{2/3}-x^{2/3})^{1/2})/(x^{1/3)}