What is the integral from 1 to 4 of 1/(w^2) ?

The integral from 1 to 4 of 1/(w^2) is 3/4

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integral from 1 to 4 of 1/(w^2)

\int_{1}^{4} \frac{1}{w ^{2}} d w

\frac{3}{4}

Decimal Notation

0.75

Solution steps

\int_{1}^{4} \frac{1}{w ^{2}} d w

Apply the Power Rule

: [- \frac{1}{w}]_{1}^{4}

= [- \frac{1}{w}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

\int (x + 2)^{2} (1 - x)^{6} d x

5 - x^{2}, sin (x), 0, 2

\frac{d ^{4}}{d x ^{4}} (8 e^{- 2 x})

\frac{d y}{d x} = (x - 2) e^{2 y}

y = (6 x^{2} - 6 x + 2) (1 + 2 x), at x = 1

What is the integral from 1 to 4 of 1/(w^2) ?
The integral from 1 to 4 of 1/(w^2) is 3/4