What is the derivative of x^3-3x ?

The derivative of x^3-3x is 3x^2-3

What is the first derivative of x^3-3x ?

The first derivative of x^3-3x is 3x^2-3

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derivative of

x^{3} - 3 x

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

= 3 x^{2} - 3

\frac{d}{d x} (x 9^{x})

\frac{d}{d x} (a x^{a - 1} ln (x) + x^{a - 1})

- \frac{6 e ^{\frac{6}{x}}}{x ^{2}}

\frac{d}{d x} (\frac{5 x ^{2}}{2 b ^{2} + x ^{2}})

(y^{2} + x y) d x + x^{2} d y = 0

What is the derivative of x^3-3x ?
The derivative of x^3-3x is 3x^2-3
What is the first derivative of x^3-3x ?
The first derivative of x^3-3x is 3x^2-3