What is the limit as x approaches 2-of sqrt(4-x^2) ?

The limit as x approaches 2-of sqrt(4-x^2) is 0

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limit as x approaches 2-of sqrt(4-x^2)

x \to 2 - lim (4 - x^{2})

0

Solution steps

x \to 2 - lim (4 - x^{2})

Plug in the value

x = 2

= 4 - 2^{2}

Simplify

= 0

n = 0 \sum \infty \frac{6}{n ^{2} - 1}

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What is the limit as x approaches 2-of sqrt(4-x^2) ?
The limit as x approaches 2-of sqrt(4-x^2) is 0