What is area sin(x),-sin(x),[0,4] ?

The answer to area sin(x),-sin(x),[0,4] is 2cos(4)+6

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area sin(x),-sin(x),[0,4]

area

sin (x), - sin (x), [0, 4]

2 cos (4) + 6

Decimal Notation

4.69271 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 2 ∣ sin (x) ∣ d x

Solve

\int_{0}^{4} 2 ∣ sin (x) ∣ d x : 2 cos (4) + 6

The area is:

= 2 cos (4) + 6

\int \frac{10 x ^{3} - 5 x ^{2} + 4 x}{x ^{2}} d x

\frac{d}{d x} (tanh (2 x - 3))

f (x) = x^{2} + x, (1, 2)

(- 1, - 4), (0, 2)

- x^{2} + 3 x + 1, - x - 1, [0, 4]

What is area sin(x),-sin(x),[0,4] ?
The answer to area sin(x),-sin(x),[0,4] is 2cos(4)+6