What is the derivative of (3x^2+4(2x-3)) ?

The derivative of (3x^2+4(2x-3)) is 18x^2-18x+8

What is the first derivative of (3x^2+4(2x-3)) ?

The first derivative of (3x^2+4(2x-3)) is 18x^2-18x+8

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\frac{d}{d x} ((3 x^{2} + 4) (2 x - 3))

18 x^{2} - 18 x + 8

Solution steps

\frac{d}{d x} ((3 x^{2} + 4) (2 x - 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x^{2} + 4, g = 2 x - 3

= \frac{d}{d x} (3 x^{2} + 4) (2 x - 3) + \frac{d}{d x} (2 x - 3) (3 x^{2} + 4)

\frac{d}{d x} (3 x^{2} + 4) = 6 x

\frac{d}{d x} (2 x - 3) = 2

= 6 x (2 x - 3) + 2 (3 x^{2} + 4)

Simplify

6 x (2 x - 3) + 2 (3 x^{2} + 4) : 18 x^{2} - 18 x + 8

= 18 x^{2} - 18 x + 8

\int \frac{5}{x} + e^{x} d x

y = 5 + 5 x^{2} - 2 x^{3}

\int (x - 5)^{2} e^{x} d x

x \to 8 + lim (\frac{1}{( x - 8 ) ^{2}})

y^{^{'}} + 3 y = 3

What is the derivative of (3x^2+4(2x-3)) ?
The derivative of (3x^2+4(2x-3)) is 18x^2-18x+8
What is the first derivative of (3x^2+4(2x-3)) ?
The first derivative of (3x^2+4(2x-3)) is 18x^2-18x+8