What is the solution for (dx}{dt}=t^5-\frac{2x)/t ?

The solution for (dx}{dt}=t^5-\frac{2x)/t is x=(t^6)/8+(c_{1})/(t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx}{dt}=t^5-\frac{2x)/t

\frac{d x}{d t} = t^{5} - \frac{2 x}{t}

x = \frac{t ^{6}}{8} + \frac{c _{1}}{t ^{2}}

Solution steps

\frac{d x}{d t} = t^{5} - \frac{2 x}{t}

Solve linear ODE:

x = \frac{t ^{6}}{8} + \frac{c _{1}}{t ^{2}}

x = \frac{t ^{6}}{8} + \frac{c _{1}}{t ^{2}}

\int_{0}^{\frac{π}{6}} x sin (x + y) d x

\frac{d}{d x} (ln (1 + 10 x))

x \to 4 + lim (2 x)

x \to 0 + lim (cot (x))

What is the solution for (dx}{dt}=t^5-\frac{2x)/t ?
The solution for (dx}{dt}=t^5-\frac{2x)/t is x=(t^6)/8+(c_{1})/(t^2)