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Popular >

integral from 0 to 2 of (2x+5)

Solution

\int_{0}^{2} (2 x + 5) d x

Solution

14

Solution steps

\int_{0}^{2} 2 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x d x + \int_{0}^{2} 5 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 5 d x = 10

= 4 + 10

Simplify

= 14

Popular Examples

(0^{2} e^{0 + 3})^{^{'}}

derivative of (x^5/(2-x^4))

\frac{d}{d x} (\frac{x ^{5}}{2 - x ^{4}})

3y^{''}-30y^'+72y=6sin(4x)

3 y^{^{''}} - 30 y^{^{'}} + 72 y = 6 sin (4 x)

integral of (3x^2+6)/((x^2-2x+2)^2)

\int \frac{3 x ^{2} + 6}{( x ^{2} - 2 x + 2 ) ^{2}} d x

derivative of sin(x^3+3xy)

\frac{d}{d x} (sin (x^{3}) + 3 x y)

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (2x+5) ?
The integral from 0 to 2 of (2x+5) is 14