What is the derivative of arccos(3x^2) ?

The derivative of arccos(3x^2) is -(6x)/(sqrt(1-9x^4))

What is the first derivative of arccos(3x^2) ?

The first derivative of arccos(3x^2) is -(6x)/(sqrt(1-9x^4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

arccos (3 x^{2})

- \frac{6 x}{1 - 9 x ^{4}}

Solution steps

\frac{d}{d x} (arccos (3 x^{2}))

Apply the chain rule:

- \frac{1}{1 - ( 3 x ^{2} ) ^{2}} \frac{d}{d x} (3 x^{2})

= - \frac{1}{1 - ( 3 x ^{2} ) ^{2}} \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

= - \frac{1}{1 - ( 3 x ^{2} ) ^{2}} \cdot 6 x

Simplify

- \frac{1}{1 - ( 3 x ^{2} ) ^{2}} \cdot 6 x : - \frac{6 x}{1 - 9 x ^{4}}

= - \frac{6 x}{1 - 9 x ^{4}}

\frac{d}{d x} (e^{1 - c o s (x)})

\frac{d}{d x} (x e^{2})

4 x (2 x - 3)^{7}

\frac{\partial}{\partial x} (x^{4} sin (2 x))

e^{- (t - 1)}

What is the derivative of arccos(3x^2) ?
The derivative of arccos(3x^2) is -(6x)/(sqrt(1-9x^4))
What is the first derivative of arccos(3x^2) ?
The first derivative of arccos(3x^2) is -(6x)/(sqrt(1-9x^4))