What is the solution for y^'+7x^{-1}y=x^2 ?

The solution for y^'+7x^{-1}y=x^2 is y=(x^3)/(10)+(c_{1})/(x^7)

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y^'+7x^{-1}y=x^2

y^{^{'}} + 7 x^{- 1} y = x^{2}

y = \frac{x ^{3}}{10} + \frac{c _{1}}{x ^{7}}

Solution steps

y^{'} (x) + 7 x^{- 1} y = x^{2}

Solve linear ODE:

y = \frac{x ^{3}}{10} + \frac{c _{1}}{x ^{7}}

y = \frac{x ^{3}}{10} + \frac{c _{1}}{x ^{7}}

10 arcsin (e^{\frac{x}{2}})

\int \frac{4 x ^{2}}{x ^{2} + 7} d x

x \to 3 lim (\frac{1}{x - 2})

y^{^{''}} - y = \frac{e ^{x}}{1 + x ^{2}}

\frac{d}{d x} (lo g_{e} (7 x^{- 2}))

What is the solution for y^'+7x^{-1}y=x^2 ?
The solution for y^'+7x^{-1}y=x^2 is y=(x^3)/(10)+(c_{1})/(x^7)