What is the tangent of y= 3/x ?

The tangent of y= 3/x is y=-3/(a_{0)^2}x+6/(a_{0)}

Popular >

tangent of y= 3/x

tangent of

y = \frac{3}{x}

y = - \frac{3}{a _{0}^{2}} x + \frac{6}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{3}{a _{0}})

Find the slope of

y = \frac{3}{x} : \frac{d y}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

y = \frac{3}{x}

x = a_{0} : m = - \frac{3}{a _{0}^{2}}

Find the line with slope m=

- \frac{3}{a _{0}^{2}}

and passing through

(a_{0}, \frac{3}{a _{0}}) : y = - \frac{3}{a _{0}^{2}} x + \frac{6}{a _{0}}

y = - \frac{3}{a _{0}^{2}} x + \frac{6}{a _{0}}

\int \frac{1}{( x ^{2} + 16 ) ^{3}} d x

\int \frac{1}{3 x ^{2} + 12} d x

\int u^{- 5} (7 - u^{5} + u^{10}) d u

\frac{d y}{d x} - 12 y = e^{9 x} y^{2}

\frac{\partial}{\partial x} (4 x y e^{x - y^{2}})

What is the tangent of y= 3/x ?
The tangent of y= 3/x is y=-3/(a_{0)^2}x+6/(a_{0)}