What is the first derivative of 8x^2 ?

The first derivative of 8x^2 is 16x

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derivative of 8x^2

derivative of

8 x^{2}

16 x

Solution steps

\frac{d}{d x} (8 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot 2 x^{2 - 1}

Simplify

= 16 x

\int 5 x^{2} \cdot e^{5 x} d x

\frac{1}{2} (2 t + 1)^{- \frac{1}{2}}

a x^{2} e^{2 x}

\frac{d}{d x} (x^{- \frac{1}{2}} sin (x))

n = 1 \sum \infty \frac{6}{n ^{2} + 2 n}