What is the limit as x approaches-1 of 4/((x+1)^2) ?

The limit as x approaches-1 of 4/((x+1)^2) is infinity

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limit as x approaches-1 of 4/((x+1)^2)

x \to - 1 lim (\frac{4}{( x + 1 ) ^{2}})

\infty

Solution steps

x \to - 1 lim (\frac{4}{( x + 1 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (\frac{4}{( x + 1 ) ^{2}}) = \infty

x \to - 1 + lim (\frac{4}{( x + 1 ) ^{2}}) = \infty

= \infty

\frac{d}{d x} (sin^{2} (\frac{x ^{2} + 1}{x}))

x \to 4 - lim (\frac{1}{4 - x})

\frac{11}{( 2 x ^{3} - 5 ) ^{4}}

\int \frac{x ^{5} + 2}{x ^{2} - 1} d x

\frac{d}{d x} (sin (x) \cdot cos (x))

What is the limit as x approaches-1 of 4/((x+1)^2) ?
The limit as x approaches-1 of 4/((x+1)^2) is infinity