What is the tangent of tan(x),\at x=-pi/3 ?

The tangent of tan(x),\at x=-pi/3 is y=4x-sqrt(3)+(4pi)/3

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tangent of tan(x),\at x=-pi/3

tangent of

tan (x), at x = - \frac{π}{3}

y = 4 x - 3 + \frac{4 π}{3}

Solution steps

Find the tangent point:

(- \frac{π}{3}, - 3)

Find the slope of

y = tan (x) : \frac{d y}{d x} = sec^{2} (x)

Compute the slope of

y = tan (x)

x = - \frac{π}{3} : m = 4

Find the line with slope m=

4

and passing through

(- \frac{π}{3}, - 3) : y = 4 x - 3 + \frac{4 π}{3}

y = 4 x - 3 + \frac{4 π}{3}

\int_{0}^{14} 10 e^{x} d x

\frac{\partial}{\partial x} (x y ln (\frac{x}{y}))

x \to - \frac{3 π}{2} - lim (tan (x))

\int_{1}^{b} \frac{1}{( x + 7 ) ^{2}} d x

\frac{d}{d x} (arccos (\frac{x}{a}))

What is the tangent of tan(x),\at x=-pi/3 ?
The tangent of tan(x),\at x=-pi/3 is y=4x-sqrt(3)+(4pi)/3