What is the integral from 0 to sqrt(3 of) 1/(1+x^2) ?

The integral from 0 to sqrt(3 of) 1/(1+x^2) is pi/3

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integral from 0 to sqrt(3 of) 1/(1+x^2)

\int_{0}^{3} \frac{1}{1 + x ^{2}} d x

\frac{π}{3}

Decimal Notation

1.04719 \dots

Solution steps

\int_{0}^{3} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{3}

Compute the boundaries:

\frac{π}{3}

= \frac{π}{3}

\int \frac{e ^{2 x}}{e ^{2 x} + 3} d x

\frac{d}{d x} (\frac{x ^{1 - a}}{1 - a})

\frac{\partial}{\partial x} ((f (x))^{^{'}})

x y^{^{''}} + y^{^{'}} = x

\frac{3 x + 4}{7 x - 5}

What is the integral from 0 to sqrt(3 of) 1/(1+x^2) ?
The integral from 0 to sqrt(3 of) 1/(1+x^2) is pi/3