What is (\partial)/(\partial z)(cos(kz-wt)) ?

The answer to (\partial)/(\partial z)(cos(kz-wt)) is -sin(kz-wt)k

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(\partial)/(\partial z)(cos(kz-wt))

\frac{\partial}{\partial z} (cos (k z - wt))

- sin (k z - wt) k

Solution steps

\frac{\partial}{\partial z} (cos (k z - wt))

Treat

k, w, t

as constants

Apply the chain rule:

- sin (k z - wt) \frac{\partial}{\partial z} (k z - wt)

= - sin (k z - wt) \frac{\partial}{\partial z} (k z - wt)

\frac{\partial}{\partial z} (k z - wt) = k

= - sin (k z - wt) k

\frac{1}{2 s ^{2} + s + 1}

x \to 1 lim ((3 x - 4)^{2})

f (x) = 5 - x^{2}

\int_{0}^{2} 2 x^{4} e^{- x} d x

y = \frac{1}{14 x ^{2}}, y = x, y = \frac{x}{10}

What is (\partial)/(\partial z)(cos(kz-wt)) ?
The answer to (\partial)/(\partial z)(cos(kz-wt)) is -sin(kz-wt)k