What is the derivative of (e^x-1/(e^x+1)) ?

The derivative of (e^x-1/(e^x+1)) is (2e^x)/((e^x+1)^2)

What is the first derivative of (e^x-1/(e^x+1)) ?

The first derivative of (e^x-1/(e^x+1)) is (2e^x)/((e^x+1)^2)

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Popular >

\frac{d}{d x} (\frac{e ^{x} - 1}{e ^{x} + 1})

\frac{2 e ^{x}}{( e ^{x} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x} - 1}{e ^{x} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} - 1 ) ( e ^{x} + 1 ) - \frac{d}{d x} ( e ^{x} + 1 ) ( e ^{x} - 1 )}{( e ^{x} + 1 ) ^{2}}

\frac{d}{d x} (e^{x} - 1) = e^{x}

\frac{d}{d x} (e^{x} + 1) = e^{x}

= \frac{e ^{x} ( e ^{x} + 1 ) - e ^{x} ( e ^{x} - 1 )}{( e ^{x} + 1 ) ^{2}}

Expand

e^{x} (e^{x} + 1) - e^{x} (e^{x} - 1) : 2 e^{x}

= \frac{2 e ^{x}}{( e ^{x} + 1 ) ^{2}}

\frac{d}{d x} (\frac{1}{( x ^{4} + 1 ) ^{3}})

4.9 x^{1.9}, at x = 1.4

\frac{d}{d x} (x^{a} ln (x))

f (x) = 5 x e^{x}

\int (x^{3} - 4 x) d x

What is the derivative of (e^x-1/(e^x+1)) ?
The derivative of (e^x-1/(e^x+1)) is (2e^x)/((e^x+1)^2)
What is the first derivative of (e^x-1/(e^x+1)) ?
The first derivative of (e^x-1/(e^x+1)) is (2e^x)/((e^x+1)^2)