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Popular >

y^'+y=8xe^x

Solution

y^{^{'}} + y = 8 x e^{x}

Solution

y = 2 e^{x} (2 x - 1) + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = 8 x e^{x}

Solve linear ODE:

y = 2 e^{x} (2 x - 1) + \frac{c _{1}}{e ^{x}}

y = 2 e^{x} (2 x - 1) + \frac{c _{1}}{e ^{x}}

Popular Examples

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x \to 0 lim (\frac{7 ^{x} - 9 ^{x}}{x})

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g (t) = 4 t^{- \frac{1}{8}}

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\int \frac{6}{3 + x ^{2}} d x

integral from (-2) to 8 of (|x-2|-3)

\int_{(- 2)}^{8} (∣ x - 2 ∣ - 3) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=8xe^x ?
The solution for y^'+y=8xe^x is y=2e^x(2x-1)+(c_{1})/(e^x)