What is area x=-2,x=1,y=2x^2+4,y=0 ?

The answer to area x=-2,x=1,y=2x^2+4,y=0 is 18

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area x=-2,x=1,y=2x^2+4,y=0

area

x = - 2, x = 1, y = 2 x^{2} + 4, y = 0

18

Solution steps

Apply the area formula:

\int_{- 2}^{1} 2 x^{2} + 4 d x

Solve

\int_{- 2}^{1} 2 x^{2} + 4 d x : 18

The area is:

= 18

\int x^{3} cos (n x) d x

x \to - 7 lim (\frac{x}{x - 2})

e^{x} + 1

x^{2} y + y^{^{'}} = - 7 x^{2}

What is area x=-2,x=1,y=2x^2+4,y=0 ?
The answer to area x=-2,x=1,y=2x^2+4,y=0 is 18