What is the solution for (dy)/(dx)=((2x(y-2)))/(x^2+1),y(0)=4 ?

The solution for (dy)/(dx)=((2x(y-2)))/(x^2+1),y(0)=4 is y=2x^2+4

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(dy)/(dx)=((2x(y-2)))/(x^2+1),y(0)=4

\frac{d y}{d x} = \frac{( 2 x ( y - 2 ) )}{x ^{2} + 1}, y (0) = 4

y = 2 x^{2} + 4

Solution steps

\frac{d y}{d x} = \frac{( 2 x ( y - 2 ) )}{x ^{2} + 1}

Solve separable ODE:

y = 2 x^{2} + 4

y = 2 x^{2} + 4

t \to 0 lim (e^{- t})

y = \frac{1}{2} (e^{x} + e^{- x})

\int 2 x (x^{2} - 7)^{99} d x

\frac{\partial}{\partial y} (e^{x y z^{8}} y z^{8})

x \to 0 lim ((sin (x))^{5 x})

What is the solution for (dy)/(dx)=((2x(y-2)))/(x^2+1),y(0)=4 ?
The solution for (dy)/(dx)=((2x(y-2)))/(x^2+1),y(0)=4 is y=2x^2+4