What is (\partial)/(\partial u)(4sin(u)cos(v)) ?

The answer to (\partial)/(\partial u)(4sin(u)cos(v)) is 4cos(v)cos(u)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial u)(4sin(u)cos(v))

\frac{\partial}{\partial u} (4 sin (u) cos (v))

4 cos (v) cos (u)

Solution steps

\frac{\partial}{\partial u} (4 sin (u) cos (v))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 cos (v) \frac{\partial}{\partial u} (sin (u))

Apply the common derivative:

\frac{\partial}{\partial u} (sin (u)) = cos (u)

= 4 cos (v) cos (u)

x \to 0 + lim (tan (2 x))

(8 x + 9)^{- 2}

\frac{d}{d x} (x^{3} - 12 x)

\int \frac{8 ( x ^{2} + 4 )}{x ( x ^{2} + 8 )} d x

What is (\partial)/(\partial u)(4sin(u)cos(v)) ?
The answer to (\partial)/(\partial u)(4sin(u)cos(v)) is 4cos(v)cos(u)