What is the derivative of 5x^3+3x^2-4x+1 ?

The derivative of 5x^3+3x^2-4x+1 is 15x^2+6x-4

What is the first derivative of 5x^3+3x^2-4x+1 ?

The first derivative of 5x^3+3x^2-4x+1 is 15x^2+6x-4

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\frac{d}{d x} (5 x^{3} + 3 x^{2} - 4 x + 1)

15 x^{2} + 6 x - 4

Solution steps

\frac{d}{d x} (5 x^{3} + 3 x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 15 x^{2} + 6 x - 4 + 0

Simplify

= 15 x^{2} + 6 x - 4

x \to 7 + lim (\frac{1}{x - 7})

\int e^{2 x + 4} d x

\frac{\partial}{\partial x} (- x (2 x - y^{3}))

\frac{d}{d x} (\frac{1}{x ^{\frac{1}{2}}})

What is the derivative of 5x^3+3x^2-4x+1 ?
The derivative of 5x^3+3x^2-4x+1 is 15x^2+6x-4
What is the first derivative of 5x^3+3x^2-4x+1 ?
The first derivative of 5x^3+3x^2-4x+1 is 15x^2+6x-4