What is the derivative of 2sin(x+4cos(x)) ?

The derivative of 2sin(x+4cos(x)) is 2cos(x)-4sin(x)

What is the first derivative of 2sin(x+4cos(x)) ?

The first derivative of 2sin(x+4cos(x)) is 2cos(x)-4sin(x)

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\frac{d}{d x} (2 sin (x) + 4 cos (x))

2 cos (x) - 4 sin (x)

Solution steps

\frac{d}{d x} (2 sin (x) + 4 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (4 cos (x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (4 cos (x)) = - 4 sin (x)

= 2 cos (x) - 4 sin (x)

\int 3 t^{5} d t

\frac{d}{d x} (x^{2} cos (π x))

\frac{d}{d x} (\frac{5}{x - 3})

\int - 4 cos (x) d x

\int_{0}^{2} e^{3 x} d x

What is the derivative of 2sin(x+4cos(x)) ?
The derivative of 2sin(x+4cos(x)) is 2cos(x)-4sin(x)
What is the first derivative of 2sin(x+4cos(x)) ?
The first derivative of 2sin(x+4cos(x)) is 2cos(x)-4sin(x)