What is the derivative of 3sin(x+4cos(x)) ?

The derivative of 3sin(x+4cos(x)) is 3cos(x)-4sin(x)

What is the first derivative of 3sin(x+4cos(x)) ?

The first derivative of 3sin(x+4cos(x)) is 3cos(x)-4sin(x)

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\frac{d}{d x} (3 sin (x) + 4 cos (x))

3 cos (x) - 4 sin (x)

Solution steps

\frac{d}{d x} (3 sin (x) + 4 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (x)) + \frac{d}{d x} (4 cos (x))

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

\frac{d}{d x} (4 cos (x)) = - 4 sin (x)

= 3 cos (x) - 4 sin (x)

\int_{1}^{2} (2 x^{3} - 4) d x

f (x) = (1 + 6 x^{2}) (x - x^{2})

n = 1 \sum \infty \frac{n x ^{n}}{n + 1}

\int_{0}^{2} (e^{x})^{2} d x

\int - x^{2} + 2 x d x

What is the derivative of 3sin(x+4cos(x)) ?
The derivative of 3sin(x+4cos(x)) is 3cos(x)-4sin(x)
What is the first derivative of 3sin(x+4cos(x)) ?
The first derivative of 3sin(x+4cos(x)) is 3cos(x)-4sin(x)