What is the derivative of 2e^{-3x} ?

The derivative of 2e^{-3x} is -6e^{-3x}

What is the first derivative of 2e^{-3x} ?

The first derivative of 2e^{-3x} is -6e^{-3x}

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derivative of

2 e^{- 3 x}

- 6 e^{- 3 x}

Solution steps

\frac{d}{d x} (2 e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{d}{d x} (- 3 x)

= e^{- 3 x} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= 2 e^{- 3 x} (- 3)

Simplify

= - 6 e^{- 3 x}

(y + 1) d x - x d y = 0

\frac{d x}{d t} = \frac{1}{( x + t + 1 )}

(- \frac{1}{5}, \frac{1}{3}), (\frac{4}{5}, - \frac{5}{3})

\frac{\partial}{\partial y} (4 x ln (x y))

\frac{d y}{d x} = \frac{5 x ^{2} + y ^{2}}{x y}

What is the derivative of 2e^{-3x} ?
The derivative of 2e^{-3x} is -6e^{-3x}
What is the first derivative of 2e^{-3x} ?
The first derivative of 2e^{-3x} is -6e^{-3x}